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Consider the figure below:
Let P and Q be points with coordinates (x PQR is right angled triangle. By Pythagoras theorem: PQ
Therefore: PQ
Find the distance between points (5,
From the above points: x Therefore by distance formula: PQ Distance =√[ (5 – 2) Distance =√[ 3 Therefore, the distance =
Prove that the Triangle with vertices given by A(3,5), B(-1,-1) and C(4,4) is a right angled triangle.
AB AB
BC BC
AC AC
Relating the three sides we found that: AB Hence Triangle ABC is the right angled triangle.
1 .Find the distance between each of the following points: (a) A(6,2) and B(-2,4) (b) C(-2,2) and D(8,-2) (c) E(3,1) and F(-2,6) (d) G(3,7) and H(9,-2) 2. Find the perimeter of triangle given by vertices (2,1) , (6,1) and (6,4) 3. Find the area of the Triangle with vertices given by A(3,5), B(-1,-1) and C(4,4) 4. Given points: A(3,1), B(0,6) and C(-5,3). Prove that triangle PQR is isosceles.
********Thanks for reading and have a nice day****** Added By (Yahyou M) - BADSHAH
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